-10(12a-39)+38=4(1-22a)-24

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Solution for -10(12a-39)+38=4(1-22a)-24 equation: 



-10(12a-39)+38=4(1-22a)-24

We move all terms to the left:

-10(12a-39)+38-(4(1-22a)-24)=0

We add all the numbers together, and all the variables

-10(12a-39)-(4(-22a+1)-24)+38=0

We multiply parentheses

-120a-(4(-22a+1)-24)+390+38=0



We calculate terms in parentheses: -(4(-22a+1)-24), so:

4(-22a+1)-24

We multiply parentheses

-88a+4-24

We add all the numbers together, and all the variables

-88a-20

Back to the equation:

-(-88a-20)



We add all the numbers together, and all the variables

-120a-(-88a-20)+428=0

We get rid of parentheses

-120a+88a+20+428=0

We add all the numbers together, and all the variables

-32a+448=0

We move all terms containing a to the left, all other terms to the right

-32a=-448

a=-448/-32

a=+14

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