-10(2x-5)+15x-30=1/3(9x-21)-(x-8)

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Solution for -10(2x-5)+15x-30=1/3(9x-21)-(x-8) equation: 



-10(2x-5)+15x-30=1/3(9x-21)-(x-8)

We move all terms to the left:

-10(2x-5)+15x-30-(1/3(9x-21)-(x-8))=0



Domain of the equation: 3(9x-21)-(x-8))!=0

x∈R



We add all the numbers together, and all the variables

15x-10(2x-5)-(1/3(9x-21)-(x-8))-30=0

We multiply parentheses

15x-20x-(1/3(9x-21)-(x-8))+50-30=0

We multiply all the terms by the denominator


15x*3(9x-21)-(x-8))-20x*3(9x-21)-(x-8))-(1+50*3(9x-21)-(x-8))-30*3(9x-21)-(x-8))=0

Wy multiply elements

45x^2(9-(x-8))-20x*3(9x-21)-(x-8))-(1+50*3(9x-21)-(x-8))-30*3(9x-21)-(x-8))=0

We add all the numbers together, and all the variables

45x^2(9-(x-8))-20x*3(9x-21)-(x-8))-(1+50*3(9x-21)-(x-8))-30*3(9x-21)-(x=0

Wy multiply elements

45x^2(9-(x-8))-60x^2(9-(x-8))-(1+150x(9-(x-8))-30*3(9x-21)-(x=0

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