-10(2x-5)=3(-8+9x)

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Solution for -10(2x-5)=3(-8+9x) equation: 



-10(2x-5)=3(-8+9x)

We move all terms to the left:

-10(2x-5)-(3(-8+9x))=0

We add all the numbers together, and all the variables

-10(2x-5)-(3(9x-8))=0

We multiply parentheses

-20x-(3(9x-8))+50=0



We calculate terms in parentheses: -(3(9x-8)), so:

3(9x-8)

We multiply parentheses

27x-24

Back to the equation:

-(27x-24)



We get rid of parentheses

-20x-27x+24+50=0

We add all the numbers together, and all the variables

-47x+74=0

We move all terms containing x to the left, all other terms to the right

-47x=-74

x=-74/-47

x=1+27/47

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