-10(a-4)=3(-4-2a)

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Solution for -10(a-4)=3(-4-2a) equation: 



-10(a-4)=3(-4-2a)

We move all terms to the left:

-10(a-4)-(3(-4-2a))=0

We add all the numbers together, and all the variables

-10(a-4)-(3(-2a-4))=0

We multiply parentheses

-10a-(3(-2a-4))+40=0



We calculate terms in parentheses: -(3(-2a-4)), so:

3(-2a-4)

We multiply parentheses

-6a-12

Back to the equation:

-(-6a-12)



We get rid of parentheses

-10a+6a+12+40=0

We add all the numbers together, and all the variables

-4a+52=0

We move all terms containing a to the left, all other terms to the right

-4a=-52

a=-52/-4

a=+13

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