-10(n+2)-3(1+n)=-62

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Solution for -10(n+2)-3(1+n)=-62 equation: 



-10(n+2)-3(1+n)=-62

We move all terms to the left:

-10(n+2)-3(1+n)-(-62)=0

We add all the numbers together, and all the variables

-10(n+2)-3(n+1)-(-62)=0

We add all the numbers together, and all the variables

-10(n+2)-3(n+1)+62=0

We multiply parentheses

-10n-3n-20-3+62=0

We add all the numbers together, and all the variables

-13n+39=0

We move all terms containing n to the left, all other terms to the right

-13n=-39

n=-39/-13

n=+3

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