-10(s2)=-62

Solution for -10(s2)=-62 equation:

-10(s2)=-62

We move all terms to the left:

-10(s2)-(-62)=0

We add all the numbers together, and all the variables

-10s^2+62=0

a = -10; b = 0; c = +62;
Δ = b2-4ac
Δ = 02-4·(-10)·62
Δ = 2480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2480}=\sqrt{16*155}=\sqrt{16}*\sqrt{155}=4\sqrt{155}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{155}}{2*-10}=\frac{0-4\sqrt{155}}{-20}
=-\frac{4\sqrt{155}}{-20}
=-\frac{\sqrt{155}}{-5}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{155}}{2*-10}=\frac{0+4\sqrt{155}}{-20}
=\frac{4\sqrt{155}}{-20}
=\frac{\sqrt{155}}{-5}
$