-10(x+1)+5(3x-4)=4(x-6)+8

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Solution for -10(x+1)+5(3x-4)=4(x-6)+8 equation: 



-10(x+1)+5(3x-4)=4(x-6)+8

We move all terms to the left:

-10(x+1)+5(3x-4)-(4(x-6)+8)=0

We multiply parentheses

-10x+15x-(4(x-6)+8)-10-20=0



We calculate terms in parentheses: -(4(x-6)+8), so:

4(x-6)+8

We multiply parentheses

4x-24+8

We add all the numbers together, and all the variables

4x-16

Back to the equation:

-(4x-16)



We add all the numbers together, and all the variables

5x-(4x-16)-30=0

We get rid of parentheses

5x-4x+16-30=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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