-10(x+2)+4(4x-7)=5(x-4)+10

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Solution for -10(x+2)+4(4x-7)=5(x-4)+10 equation:



-10(x+2)+4(4x-7)=5(x-4)+10
We move all terms to the left:
-10(x+2)+4(4x-7)-(5(x-4)+10)=0
We multiply parentheses
-10x+16x-(5(x-4)+10)-20-28=0
We calculate terms in parentheses: -(5(x-4)+10), so:
5(x-4)+10
We multiply parentheses
5x-20+10
We add all the numbers together, and all the variables
5x-10
Back to the equation:
-(5x-10)
We add all the numbers together, and all the variables
6x-(5x-10)-48=0
We get rid of parentheses
6x-5x+10-48=0
We add all the numbers together, and all the variables
x-38=0
We move all terms containing x to the left, all other terms to the right
x=38

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