-10(x+3)+5(3x-5)=4(x-4)+12

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Solution for -10(x+3)+5(3x-5)=4(x-4)+12 equation: 



-10(x+3)+5(3x-5)=4(x-4)+12

We move all terms to the left:

-10(x+3)+5(3x-5)-(4(x-4)+12)=0

We multiply parentheses

-10x+15x-(4(x-4)+12)-30-25=0



We calculate terms in parentheses: -(4(x-4)+12), so:

4(x-4)+12

We multiply parentheses

4x-16+12

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

5x-(4x-4)-55=0

We get rid of parentheses

5x-4x+4-55=0

We add all the numbers together, and all the variables

x-51=0

We move all terms containing x to the left, all other terms to the right

x=51

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