-10(x-2)+20x=10(x+4)-20

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Solution for -10(x-2)+20x=10(x+4)-20 equation: 


Simplifying
-10(x + -2) + 20x = 10(x + 4) + -20

Reorder the terms:
-10(-2 + x) + 20x = 10(x + 4) + -20
(-2 * -10 + x * -10) + 20x = 10(x + 4) + -20
(20 + -10x) + 20x = 10(x + 4) + -20

Combine like terms: -10x + 20x = 10x
20 + 10x = 10(x + 4) + -20

Reorder the terms:
20 + 10x = 10(4 + x) + -20
20 + 10x = (4 * 10 + x * 10) + -20
20 + 10x = (40 + 10x) + -20

Reorder the terms:
20 + 10x = 40 + -20 + 10x

Combine like terms: 40 + -20 = 20
20 + 10x = 20 + 10x

Add '-20' to each side of the equation.
20 + -20 + 10x = 20 + -20 + 10x

Combine like terms: 20 + -20 = 0
0 + 10x = 20 + -20 + 10x
10x = 20 + -20 + 10x

Combine like terms: 20 + -20 = 0
10x = 0 + 10x
10x = 10x

Add '-10x' to each side of the equation.
10x + -10x = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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