-10(z+1)+4(4z-7)=5(z-6)+12

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Solution for -10(z+1)+4(4z-7)=5(z-6)+12 equation: 



-10(z+1)+4(4z-7)=5(z-6)+12

We move all terms to the left:

-10(z+1)+4(4z-7)-(5(z-6)+12)=0

We multiply parentheses

-10z+16z-(5(z-6)+12)-10-28=0



We calculate terms in parentheses: -(5(z-6)+12), so:

5(z-6)+12

We multiply parentheses

5z-30+12

We add all the numbers together, and all the variables

5z-18

Back to the equation:

-(5z-18)



We add all the numbers together, and all the variables

6z-(5z-18)-38=0

We get rid of parentheses

6z-5z+18-38=0

We add all the numbers together, and all the variables

z-20=0

We move all terms containing z to the left, all other terms to the right

z=20

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