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-10(z+1)+4(4z-7)=5(z-6)+12
We move all terms to the left:
-10(z+1)+4(4z-7)-(5(z-6)+12)=0
We multiply parentheses
-10z+16z-(5(z-6)+12)-10-28=0
We calculate terms in parentheses: -(5(z-6)+12), so:We add all the numbers together, and all the variables
5(z-6)+12
We multiply parentheses
5z-30+12
We add all the numbers together, and all the variables
5z-18
Back to the equation:
-(5z-18)
6z-(5z-18)-38=0
We get rid of parentheses
6z-5z+18-38=0
We add all the numbers together, and all the variables
z-20=0
We move all terms containing z to the left, all other terms to the right
z=20
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