-10(z+1)+5(3z-3)=4(z-3)10

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Solution for -10(z+1)+5(3z-3)=4(z-3)10 equation: 



-10(z+1)+5(3z-3)=4(z-3)10

We move all terms to the left:

-10(z+1)+5(3z-3)-(4(z-3)10)=0

We multiply parentheses

-10z+15z-(4(z-3)10)-10-15=0



We calculate terms in parentheses: -(4(z-3)10), so:

4(z-3)10

We multiply parentheses

40z-120

Back to the equation:

-(40z-120)



We add all the numbers together, and all the variables

5z-(40z-120)-25=0

We get rid of parentheses

5z-40z+120-25=0

We add all the numbers together, and all the variables

-35z+95=0

We move all terms containing z to the left, all other terms to the right

-35z=-95

z=-95/-35

z=2+5/7

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