-10(z+5)=-4z-4(2z+7)

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Solution for -10(z+5)=-4z-4(2z+7) equation: 



-10(z+5)=-4z-4(2z+7)

We move all terms to the left:

-10(z+5)-(-4z-4(2z+7))=0

We multiply parentheses

-10z-(-4z-4(2z+7))-50=0



We calculate terms in parentheses: -(-4z-4(2z+7)), so:

-4z-4(2z+7)

We multiply parentheses

-4z-8z-28

We add all the numbers together, and all the variables

-12z-28

Back to the equation:

-(-12z-28)



We get rid of parentheses

-10z+12z+28-50=0

We add all the numbers together, and all the variables

2z-22=0

We move all terms containing z to the left, all other terms to the right

2z=22

z=22/2

z=11

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