-10+-40b+12=-14b-48-6

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Solution for -10+-40b+12=-14b-48-6 equation: 



-10+-40b+12=-14b-48-6

We move all terms to the left:

-10+-40b+12-(-14b-48-6)=0

We add all the numbers together, and all the variables

-40b-(-14b-54)-10+12+=0

We add all the numbers together, and all the variables

-40b-(-14b-54)=0

We get rid of parentheses

-40b+14b+54=0

We add all the numbers together, and all the variables

-26b+54=0

We move all terms containing b to the left, all other terms to the right

-26b=-54

b=-54/-26

b=2+1/13

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