-10+2(5-2x)=6(x+1)-8x-2x

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Solution for -10+2(5-2x)=6(x+1)-8x-2x equation: 



-10+2(5-2x)=6(x+1)-8x-2x

We move all terms to the left:

-10+2(5-2x)-(6(x+1)-8x-2x)=0

We add all the numbers together, and all the variables

2(-2x+5)-(6(x+1)-8x-2x)-10=0

We multiply parentheses

-4x-(6(x+1)-8x-2x)+10-10=0



We calculate terms in parentheses: -(6(x+1)-8x-2x), so:

6(x+1)-8x-2x

We add all the numbers together, and all the variables

-10x+6(x+1)

We multiply parentheses

-10x+6x+6

We add all the numbers together, and all the variables

-4x+6

Back to the equation:

-(-4x+6)



We add all the numbers together, and all the variables

-4x-(-4x+6)=0

We get rid of parentheses

-4x+4x-6=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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