-10+2v=5(-2+5v)+6v

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Solution for -10+2v=5(-2+5v)+6v equation: 



-10+2v=5(-2+5v)+6v

We move all terms to the left:

-10+2v-(5(-2+5v)+6v)=0

We add all the numbers together, and all the variables

2v-(5(5v-2)+6v)-10=0



We calculate terms in parentheses: -(5(5v-2)+6v), so:

5(5v-2)+6v

We add all the numbers together, and all the variables

6v+5(5v-2)

We multiply parentheses

6v+25v-10

We add all the numbers together, and all the variables

31v-10

Back to the equation:

-(31v-10)



We get rid of parentheses

2v-31v+10-10=0

We add all the numbers together, and all the variables

-29v=0

v=0/-29

v=0

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