-10+2x+3(5-x)=2(x-2)

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Solution for -10+2x+3(5-x)=2(x-2) equation: 



-10+2x+3(5-x)=2(x-2)

We move all terms to the left:

-10+2x+3(5-x)-(2(x-2))=0

We add all the numbers together, and all the variables

2x+3(-1x+5)-(2(x-2))-10=0

We multiply parentheses

2x-3x-(2(x-2))+15-10=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

-1x-(2x-4)+5=0

We get rid of parentheses

-1x-2x+4+5=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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