-10+3b=5b-2(b+5)

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Solution for -10+3b=5b-2(b+5) equation: 



-10+3b=5b-2(b+5)

We move all terms to the left:

-10+3b-(5b-2(b+5))=0



We calculate terms in parentheses: -(5b-2(b+5)), so:

5b-2(b+5)

We multiply parentheses

5b-2b-10

We add all the numbers together, and all the variables

3b-10

Back to the equation:

-(3b-10)



We get rid of parentheses

3b-3b+10-10=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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