-10+7(j+3)=4(2j-1)+5

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Solution for -10+7(j+3)=4(2j-1)+5 equation: 



-10+7(j+3)=4(2j-1)+5

We move all terms to the left:

-10+7(j+3)-(4(2j-1)+5)=0

We multiply parentheses

7j-(4(2j-1)+5)+21-10=0



We calculate terms in parentheses: -(4(2j-1)+5), so:

4(2j-1)+5

We multiply parentheses

8j-4+5

We add all the numbers together, and all the variables

8j+1

Back to the equation:

-(8j+1)



We add all the numbers together, and all the variables

7j-(8j+1)+11=0

We get rid of parentheses

7j-8j-1+11=0

We add all the numbers together, and all the variables

-1j+10=0

We move all terms containing j to the left, all other terms to the right

-j=-10

j=-10/-1

j=+10

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