-10-10f=2(-10f+10)+7f

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Solution for -10-10f=2(-10f+10)+7f equation: 



-10-10f=2(-10f+10)+7f

We move all terms to the left:

-10-10f-(2(-10f+10)+7f)=0



We calculate terms in parentheses: -(2(-10f+10)+7f), so:

2(-10f+10)+7f

We add all the numbers together, and all the variables

7f+2(-10f+10)

We multiply parentheses

7f-20f+20

We add all the numbers together, and all the variables

-13f+20

Back to the equation:

-(-13f+20)



We get rid of parentheses

-10f+13f-20-10=0

We add all the numbers together, and all the variables

3f-30=0

We move all terms containing f to the left, all other terms to the right

3f=30

f=30/3

f=10

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