-10-10f=2(-10f+10)+7f

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Solution for -10-10f=2(-10f+10)+7f equation:



-10-10f=2(-10f+10)+7f
We move all terms to the left:
-10-10f-(2(-10f+10)+7f)=0
We calculate terms in parentheses: -(2(-10f+10)+7f), so:
2(-10f+10)+7f
We add all the numbers together, and all the variables
7f+2(-10f+10)
We multiply parentheses
7f-20f+20
We add all the numbers together, and all the variables
-13f+20
Back to the equation:
-(-13f+20)
We get rid of parentheses
-10f+13f-20-10=0
We add all the numbers together, and all the variables
3f-30=0
We move all terms containing f to the left, all other terms to the right
3f=30
f=30/3
f=10

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