-10-2(x+4)+2x=6x+20

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Solution for -10-2(x+4)+2x=6x+20 equation: 



-10-2(x+4)+2x=6x+20

We move all terms to the left:

-10-2(x+4)+2x-(6x+20)=0

We add all the numbers together, and all the variables

2x-2(x+4)-(6x+20)-10=0

We multiply parentheses

2x-2x-(6x+20)-8-10=0

We get rid of parentheses

2x-2x-6x-20-8-10=0

We add all the numbers together, and all the variables

-6x-38=0

We move all terms containing x to the left, all other terms to the right

-6x=38

x=38/-6

x=-6+1/3

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