-10-40b+12=-42b-48+6

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Solution for -10-40b+12=-42b-48+6 equation:



-10-40b+12=-42b-48+6
We move all terms to the left:
-10-40b+12-(-42b-48+6)=0
We add all the numbers together, and all the variables
-40b-(-42b-42)-10+12=0
We add all the numbers together, and all the variables
-40b-(-42b-42)+2=0
We get rid of parentheses
-40b+42b+42+2=0
We add all the numbers together, and all the variables
2b+44=0
We move all terms containing b to the left, all other terms to the right
2b=-44
b=-44/2
b=-22

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