-10/13=cos180/28(x-15)

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Solution for -10/13=cos180/28(x-15) equation: 


(b^2)/(b^-2) = 0

t/32 = 8

sin(0.01*2*10*pi)

x^(10^3)*((7.5*x^(10^8))/3) = 0

(3/2)*X-Y = 22

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