-103+3x=41+12x

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Solution for -103+3x=41+12x equation: 



-103+3x=41+12x

We move all terms to the left:

-103+3x-(41+12x)=0

We add all the numbers together, and all the variables

3x-(12x+41)-103=0

We get rid of parentheses

3x-12x-41-103=0

We add all the numbers together, and all the variables

-9x-144=0

We move all terms containing x to the left, all other terms to the right

-9x=144

x=144/-9

x=-16

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