-105+7y+5=4(4y-4)-3

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Solution for -105+7y+5=4(4y-4)-3 equation:



-105+7y+5=4(4y-4)-3
We move all terms to the left:
-105+7y+5-(4(4y-4)-3)=0
We add all the numbers together, and all the variables
7y-(4(4y-4)-3)-100=0
We calculate terms in parentheses: -(4(4y-4)-3), so:
4(4y-4)-3
We multiply parentheses
16y-16-3
We add all the numbers together, and all the variables
16y-19
Back to the equation:
-(16y-19)
We get rid of parentheses
7y-16y+19-100=0
We add all the numbers together, and all the variables
-9y-81=0
We move all terms containing y to the left, all other terms to the right
-9y=81
y=81/-9
y=-9

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