-10=(-1/3)(6)+b

Solution for -10=(-1/3)(6)+b equation:

-10=(-1/3)(6)+b

We move all terms to the left:

-10-((-1/3)(6)+b)=0


Domain of the equation: 3)6+b)!=0

b!=0/1

b!=0

b∈R


We multiply all the terms by the denominator


-((-1-10*3)6+b)=0


We calculate terms in parentheses: -((-1-10*3)6+b), so:

(-1-10*3)6+b

determiningTheFunctionDomain
b+(-1-10*3)6

We add all the numbers together, and all the variables

b+(-31)6

We add all the numbers together, and all the variables

b-186

Back to the equation:

-(b-186)


We get rid of parentheses

-b+186=0

We add all the numbers together, and all the variables

-1b+186=0

We move all terms containing b to the left, all other terms to the right

-b=-186

b=-186/-1

b=+186