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-10=1/2x+x
We move all terms to the left:
-10-(1/2x+x)=0
Domain of the equation: 2x+x)!=0We add all the numbers together, and all the variables
x∈R
-(+x+1/2x)-10=0
We get rid of parentheses
-x-1/2x-10=0
We multiply all the terms by the denominator
-x*2x-10*2x-1=0
Wy multiply elements
-2x^2-20x-1=0
a = -2; b = -20; c = -1;
Δ = b2-4ac
Δ = -202-4·(-2)·(-1)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-14\sqrt{2}}{2*-2}=\frac{20-14\sqrt{2}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+14\sqrt{2}}{2*-2}=\frac{20+14\sqrt{2}}{-4} $
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