-10=2(w-3)6w

Solution for -10=2(w-3)6w equation:

-10=2(w-3)6w

We move all terms to the left:

-10-(2(w-3)6w)=0


We calculate terms in parentheses: -(2(w-3)6w), so:

2(w-3)6w

We multiply parentheses

12w^2-36w

Back to the equation:

-(12w^2-36w)


We get rid of parentheses

-12w^2+36w-10=0

a = -12; b = 36; c = -10;
Δ = b2-4ac
Δ = 362-4·(-12)·(-10)
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{51}}{2*-12}=\frac{-36-4\sqrt{51}}{-24}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{51}}{2*-12}=\frac{-36+4\sqrt{51}}{-24}
$