-10=2/3(k-9)

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Solution for -10=2/3(k-9) equation:



-10=2/3(k-9)
We move all terms to the left:
-10-(2/3(k-9))=0
Domain of the equation: 3(k-9))!=0
k∈R
We multiply all the terms by the denominator
-(2-10*3(k-9))=0
We calculate terms in parentheses: -(2-10*3(k-9)), so:
2-10*3(k-9)
determiningTheFunctionDomain -10*3(k-9)+2
Wy multiply elements
-30k(k+2
Back to the equation:
-(-30k(k+2)
We calculate terms in parentheses: -(-30k(k+2), so:
-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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-30k(k+2
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