-10=2f/5;f=

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Solution for -10=2f/5;f= equation: 



-10=2f/5f=

We move all terms to the left:

-10-(2f/5f)=0



Domain of the equation: 5f)!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

-(+2f/5f)-10=0

We get rid of parentheses

-2f/5f-10=0

We multiply all the terms by the denominator


-2f-10*5f=0

Wy multiply elements

-2f-50f=0

We add all the numbers together, and all the variables

-52f=0

f=0/-52

f=0

Równanie nie ma rozwiązania

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