-10=2x(-8x+35)

Solution for -10=2x(-8x+35) equation:

-10=2x(-8x+35)

We move all terms to the left:

-10-(2x(-8x+35))=0


We calculate terms in parentheses: -(2x(-8x+35)), so:

2x(-8x+35)

We multiply parentheses

-16x^2+70x

Back to the equation:

-(-16x^2+70x)


We get rid of parentheses

16x^2-70x-10=0

a = 16; b = -70; c = -10;
Δ = b2-4ac
Δ = -702-4·16·(-10)
Δ = 5540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5540}=\sqrt{4*1385}=\sqrt{4}*\sqrt{1385}=2\sqrt{1385}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2\sqrt{1385}}{2*16}=\frac{70-2\sqrt{1385}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2\sqrt{1385}}{2*16}=\frac{70+2\sqrt{1385}}{32}
$