-10=3-(9-z)

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Solution for -10=3-(9-z) equation: 



-10=3-(9-z)

We move all terms to the left:

-10-(3-(9-z))=0

We add all the numbers together, and all the variables

-(3-(-1z+9))-10=0



We calculate terms in parentheses: -(3-(-1z+9)), so:

3-(-1z+9)

determiningTheFunctionDomain
-(-1z+9)+3

We get rid of parentheses

1z-9+3

We add all the numbers together, and all the variables

z-6

Back to the equation:

-(z-6)



We get rid of parentheses

-z+6-10=0

We add all the numbers together, and all the variables

-1z-4=0

We move all terms containing z to the left, all other terms to the right

-z=4

z=4/-1

z=-4

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