-10b+6+4b-3=-5(b+1)-8

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Solution for -10b+6+4b-3=-5(b+1)-8 equation: 



-10b+6+4b-3=-5(b+1)-8

We move all terms to the left:

-10b+6+4b-3-(-5(b+1)-8)=0

We add all the numbers together, and all the variables

-6b-(-5(b+1)-8)+3=0



We calculate terms in parentheses: -(-5(b+1)-8), so:

-5(b+1)-8

We multiply parentheses

-5b-5-8

We add all the numbers together, and all the variables

-5b-13

Back to the equation:

-(-5b-13)



We get rid of parentheses

-6b+5b+13+3=0

We add all the numbers together, and all the variables

-1b+16=0

We move all terms containing b to the left, all other terms to the right

-b=-16

b=-16/-1

b=+16

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