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-10c(c+11)=-20
We move all terms to the left:
-10c(c+11)-(-20)=0
We add all the numbers together, and all the variables
-10c(c+11)+20=0
We multiply parentheses
-10c^2-110c+20=0
a = -10; b = -110; c = +20;
Δ = b2-4ac
Δ = -1102-4·(-10)·20
Δ = 12900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12900}=\sqrt{100*129}=\sqrt{100}*\sqrt{129}=10\sqrt{129}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-10\sqrt{129}}{2*-10}=\frac{110-10\sqrt{129}}{-20} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+10\sqrt{129}}{2*-10}=\frac{110+10\sqrt{129}}{-20} $
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