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-10h+3=(17-28h)/8
We move all terms to the left:
-10h+3-((17-28h)/8)=0
We add all the numbers together, and all the variables
-10h-((-28h+17)/8)+3=0
We multiply all the terms by the denominator
-10h*8)-((-28h+17)+3*8)=0
We add all the numbers together, and all the variables
-10h*8)-((-28h+17)=0
Wy multiply elements
-80h^2=0
a = -80; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-80)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$h=\frac{-b}{2a}=\frac{0}{-160}=0$
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