-10q+5(1-q)=25q+65(1-q)

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Solution for -10q+5(1-q)=25q+65(1-q) equation: 



-10q+5(1-q)=25q+65(1-q)

We move all terms to the left:

-10q+5(1-q)-(25q+65(1-q))=0

We add all the numbers together, and all the variables

-10q+5(-1q+1)-(25q+65(-1q+1))=0

We multiply parentheses

-10q-5q-(25q+65(-1q+1))+5=0



We calculate terms in parentheses: -(25q+65(-1q+1)), so:

25q+65(-1q+1)

We multiply parentheses

25q-65q+65

We add all the numbers together, and all the variables

-40q+65

Back to the equation:

-(-40q+65)



We add all the numbers together, and all the variables

-15q-(-40q+65)+5=0

We get rid of parentheses

-15q+40q-65+5=0

We add all the numbers together, and all the variables

25q-60=0

We move all terms containing q to the left, all other terms to the right

25q=60

q=60/25

q=2+2/5

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