-10x(5x+10)=-2x(10x-4)

Solution for -10x(5x+10)=-2x(10x-4) equation:

-10x(5x+10)=-2x(10x-4)

We move all terms to the left:

-10x(5x+10)-(-2x(10x-4))=0

We multiply parentheses

-50x^2-100x-(-2x(10x-4))=0


We calculate terms in parentheses: -(-2x(10x-4)), so:

-2x(10x-4)

We multiply parentheses

-20x^2+8x

Back to the equation:

-(-20x^2+8x)


We get rid of parentheses

-50x^2+20x^2-8x-100x=0

We add all the numbers together, and all the variables

-30x^2-108x=0

a = -30; b = -108; c = 0;
Δ = b2-4ac
Δ = -1082-4·(-30)·0
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-108}{2*-30}=\frac{0}{-60}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+108}{2*-30}=\frac{216}{-60}
=-3+3/5
$