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-10x(x-3)=8x
We move all terms to the left:
-10x(x-3)-(8x)=0
We add all the numbers together, and all the variables
-8x-10x(x-3)=0
We multiply parentheses
-10x^2-8x+30x=0
We add all the numbers together, and all the variables
-10x^2+22x=0
a = -10; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-10)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-10}=\frac{-44}{-20} =2+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-10}=\frac{0}{-20} =0 $
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