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-10x+18=-3x(5x-7)+5x
We move all terms to the left:
-10x+18-(-3x(5x-7)+5x)=0
We calculate terms in parentheses: -(-3x(5x-7)+5x), so:We get rid of parentheses
-3x(5x-7)+5x
We add all the numbers together, and all the variables
5x-3x(5x-7)
We multiply parentheses
-15x^2+5x+21x
We add all the numbers together, and all the variables
-15x^2+26x
Back to the equation:
-(-15x^2+26x)
15x^2-26x-10x+18=0
We add all the numbers together, and all the variables
15x^2-36x+18=0
a = 15; b = -36; c = +18;
Δ = b2-4ac
Δ = -362-4·15·18
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{6}}{2*15}=\frac{36-6\sqrt{6}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{6}}{2*15}=\frac{36+6\sqrt{6}}{30} $
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