-10x+3(8+8x)=6(x-4)

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Solution for -10x+3(8+8x)=6(x-4) equation: 



-10x+3(8+8x)=6(x-4)

We move all terms to the left:

-10x+3(8+8x)-(6(x-4))=0

We add all the numbers together, and all the variables

-10x+3(8x+8)-(6(x-4))=0

We multiply parentheses

-10x+24x-(6(x-4))+24=0



We calculate terms in parentheses: -(6(x-4)), so:

6(x-4)

We multiply parentheses

6x-24

Back to the equation:

-(6x-24)



We add all the numbers together, and all the variables

14x-(6x-24)+24=0

We get rid of parentheses

14x-6x+24+24=0

We add all the numbers together, and all the variables

8x+48=0

We move all terms containing x to the left, all other terms to the right

8x=-48

x=-48/8

x=-6

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