-10x+5-4(x-1)=-4x(9x-4)+4

Solution for -10x+5-4(x-1)=-4x(9x-4)+4 equation:

-10x+5-4(x-1)=-4x(9x-4)+4

We move all terms to the left:

-10x+5-4(x-1)-(-4x(9x-4)+4)=0

We multiply parentheses

-10x-4x-(-4x(9x-4)+4)+4+5=0


We calculate terms in parentheses: -(-4x(9x-4)+4), so:

-4x(9x-4)+4

We multiply parentheses

-36x^2+16x+4

Back to the equation:

-(-36x^2+16x+4)


We add all the numbers together, and all the variables

-(-36x^2+16x+4)-14x+9=0

We get rid of parentheses

36x^2-16x-14x-4+9=0

We add all the numbers together, and all the variables

36x^2-30x+5=0

a = 36; b = -30; c = +5;
Δ = b2-4ac
Δ = -302-4·36·5
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6\sqrt{5}}{2*36}=\frac{30-6\sqrt{5}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6\sqrt{5}}{2*36}=\frac{30+6\sqrt{5}}{72}
$