-10x2+3x+27=0

Solution for -10x2+3x+27=0 equation:

-10x^2+3x+27=0

a = -10; b = 3; c = +27;
Δ = b2-4ac
Δ = 32-4·(-10)·27
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*-10}=\frac{-36}{-20}
=1+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*-10}=\frac{30}{-20}
=-1+1/2
$