-10x2=-8x-8

Solution for -10x2=-8x-8 equation:

-10x^2=-8x-8

We move all terms to the left:

-10x^2-(-8x-8)=0

We get rid of parentheses

-10x^2+8x+8=0

a = -10; b = 8; c = +8;
Δ = b2-4ac
Δ = 82-4·(-10)·8
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{6}}{2*-10}=\frac{-8-8\sqrt{6}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{6}}{2*-10}=\frac{-8+8\sqrt{6}}{-20}
$