-10y+3(8+8y)=-6(y+4)

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Solution for -10y+3(8+8y)=-6(y+4) equation: 



-10y+3(8+8y)=-6(y+4)

We move all terms to the left:

-10y+3(8+8y)-(-6(y+4))=0

We add all the numbers together, and all the variables

-10y+3(8y+8)-(-6(y+4))=0

We multiply parentheses

-10y+24y-(-6(y+4))+24=0



We calculate terms in parentheses: -(-6(y+4)), so:

-6(y+4)

We multiply parentheses

-6y-24

Back to the equation:

-(-6y-24)



We add all the numbers together, and all the variables

14y-(-6y-24)+24=0

We get rid of parentheses

14y+6y+24+24=0

We add all the numbers together, and all the variables

20y+48=0

We move all terms containing y to the left, all other terms to the right

20y=-48

y=-48/20

y=-2+2/5

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