-10y=-3+6(y-2)-y

Solution for -10y=-3+6(y-2)-y equation:

-10y=-3+6(y-2)-y

We move all terms to the left:

-10y-(-3+6(y-2)-y)=0


We calculate terms in parentheses: -(-3+6(y-2)-y), so:

-3+6(y-2)-y

determiningTheFunctionDomain
6(y-2)-y-3

We add all the numbers together, and all the variables

-1y+6(y-2)-3

We multiply parentheses

-1y+6y-12-3

We add all the numbers together, and all the variables

5y-15

Back to the equation:

-(5y-15)


We get rid of parentheses

-10y-5y+15=0

We add all the numbers together, and all the variables

-15y+15=0

We move all terms containing y to the left, all other terms to the right

-15y=-15

y=-15/-15

y=1