-10z-(14z+2)=2+(3z+4)

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Solution for -10z-(14z+2)=2+(3z+4) equation:



-10z-(14z+2)=2+(3z+4)
We move all terms to the left:
-10z-(14z+2)-(2+(3z+4))=0
We get rid of parentheses
-10z-14z-(2+(3z+4))-2=0
We calculate terms in parentheses: -(2+(3z+4)), so:
2+(3z+4)
determiningTheFunctionDomain (3z+4)+2
We get rid of parentheses
3z+4+2
We add all the numbers together, and all the variables
3z+6
Back to the equation:
-(3z+6)
We add all the numbers together, and all the variables
-24z-(3z+6)-2=0
We get rid of parentheses
-24z-3z-6-2=0
We add all the numbers together, and all the variables
-27z-8=0
We move all terms containing z to the left, all other terms to the right
-27z=8
z=8/-27
z=-8/27

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