-11(6+2v)-2v=-2(1+8v)

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Solution for -11(6+2v)-2v=-2(1+8v) equation: 



-11(6+2v)-2v=-2(1+8v)

We move all terms to the left:

-11(6+2v)-2v-(-2(1+8v))=0

We add all the numbers together, and all the variables

-11(2v+6)-2v-(-2(8v+1))=0

We add all the numbers together, and all the variables

-2v-11(2v+6)-(-2(8v+1))=0

We multiply parentheses

-2v-22v-(-2(8v+1))-66=0



We calculate terms in parentheses: -(-2(8v+1)), so:

-2(8v+1)

We multiply parentheses

-16v-2

Back to the equation:

-(-16v-2)



We add all the numbers together, and all the variables

-24v-(-16v-2)-66=0

We get rid of parentheses

-24v+16v+2-66=0

We add all the numbers together, and all the variables

-8v-64=0

We move all terms containing v to the left, all other terms to the right

-8v=64

v=64/-8

v=-8

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