-11(b+9)=3(-33-b)

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Solution for -11(b+9)=3(-33-b) equation: 



-11(b+9)=3(-33-b)

We move all terms to the left:

-11(b+9)-(3(-33-b))=0

We add all the numbers together, and all the variables

-11(b+9)-(3(-1b-33))=0

We multiply parentheses

-11b-(3(-1b-33))-99=0



We calculate terms in parentheses: -(3(-1b-33)), so:

3(-1b-33)

We multiply parentheses

-3b-99

Back to the equation:

-(-3b-99)



We get rid of parentheses

-11b+3b+99-99=0

We add all the numbers together, and all the variables

-8b=0

b=0/-8

b=0

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