-11(k+3)=2(-9-7k)

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Solution for -11(k+3)=2(-9-7k) equation: 



-11(k+3)=2(-9-7k)

We move all terms to the left:

-11(k+3)-(2(-9-7k))=0

We add all the numbers together, and all the variables

-11(k+3)-(2(-7k-9))=0

We multiply parentheses

-11k-(2(-7k-9))-33=0



We calculate terms in parentheses: -(2(-7k-9)), so:

2(-7k-9)

We multiply parentheses

-14k-18

Back to the equation:

-(-14k-18)



We get rid of parentheses

-11k+14k+18-33=0

We add all the numbers together, and all the variables

3k-15=0

We move all terms containing k to the left, all other terms to the right

3k=15

k=15/3

k=5

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