-11(y+3)6(3y-4)=6(y-3)+8

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Solution for -11(y+3)6(3y-4)=6(y-3)+8 equation: 



-11(y+3)6(3y-4)=6(y-3)+8

We move all terms to the left:

-11(y+3)6(3y-4)-(6(y-3)+8)=0



We calculate terms in parentheses: -(6(y-3)+8), so:

6(y-3)+8

We multiply parentheses

6y-18+8

We add all the numbers together, and all the variables

6y-10

Back to the equation:

-(6y-10)



We get rid of parentheses

-11(y+3)6(3y-4)-6y+10=0

We add all the numbers together, and all the variables

-6y-11(y+3)6(3y-4)+10=0

We move all terms containing y to the left, all other terms to the right

-6y-11(y+3)6(3y-4)=-10

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